New 1z1-071 Test Materials & Valid 1z1-071 Test Engine
1z1-071 Updated Exam Dumps [2024] Practice Valid Exam Dumps Question
1z1-071 certification exam is designed to validate the skills and knowledge of professionals working with Oracle Database technology. It is a crucial exam for individuals who want to prove their proficiency in SQL language and database management system. 1z1-071 exam is designed to test the candidate's knowledge of using SQL to manage and manipulate data in the Oracle database.
Oracle 1z1-071 (Oracle Database SQL) Exam is a certification exam offered by Oracle Corporation for individuals looking to demonstrate their proficiency in SQL and Oracle Database. 1z1-071 exam is designed to test the candidate's knowledge and skills in SQL language, data modeling, database concepts, and the use of Oracle Database software. Passing 1z1-071 exam validates the candidate's ability to work with Oracle Database and SQL, making them a valuable asset to any organization that uses these technologies.
NEW QUESTION # 73
View the Exhibit and examine the structure of the SALES and PRODUCTS tables. (Choose two.)
In the SALES table, PROD_ID is the foreign key referencing PROD_ID in the PRODUCTS table. You must list each product ID and the number of times it has been sold.
Examine this query which is missing a JOIN operator:
SQL > SELECT p.prod_id, count(s.prod_id)
FROM products p ______________ sales s
ON p.prod_id = s.prod_id
GROUP BY p.prod_id;
Which two JOIN operations can be used to obtain the required output?
- A. LEFT OUETR JOIN
- B. FULL OUTER JOIN
- C. RIGHT OUTER JOIN
- D. JOIN
Answer: A,B
NEW QUESTION # 74
The CUSTOMERS table has a CUST_CREDIT_LIMIT column of data type NUMBER.
Which two queries execute successfully?
- A. SELECT NVL2(cust_credit_limit, TO_CHAR(cust_credit_limit * .15), 'Not Available') FROM customers;
- B. SELECT NVL2 (cust_credit_limit * .15, 'Not Available') FROM customers;
- C. SELECT NVL (cust_credit_limit * .15, 'Not Available') FROM customers;
- D. SELECT TO_CHAR(NVL(cust_credit_limit * .15, 'Not Available')) FROM customers;
- E. SELECT NVL(TO_CHAR(cust_credit_limit * .15), 'Not Available') FROM customers;
Answer: B,E
NEW QUESTION # 75
View the Exhibit and examine the structure of ORDERS and CUSTOMERS tables.
(Choose the best answer.)
You executed this UPDATE statement:
UPDATE
( SELECT order_date, order_total, customer_id FROM orders)
Set order_date = '22-mar-2007'
WHERE customer_id IN
(SELECT customer_id FROM customers
WHERE cust_last_name = 'Roberts' AND credit_limit = 600);
Which statement is true regarding the execution?
- A. It would not execute because two tables cannot be referenced in a single UPDATE statement.
- B. It would not execute because a subquery cannot be used in the WHERE clause of an UPDATE statement.
- C. It would execute and restrict modifications to the columns specified in the SELECT statement.
- D. It would not execute because a SELECT statement cannot be used in place of a table name.
Answer: C
NEW QUESTION # 76
Examine the structure of the INVOICEtable.
Which two SQL statements would execute successfully?
- A. SELECT inv_no, NVL2(inv_date, sysdate-inv_date, sysdate)
FROM invoice; - B. SELECT inv_no, NVL2(inv_date, 'Pending', 'Incomplete')
FROM invoice; - C. SELECT inv_no, NVL2(inv_amt, inv_amt*.25, 'Not Available')
FROM invoice; - D. SELECT inv_no, NVL2(inv_amt, inv_date, 'Not Available')
FROM invoice;
Answer: A,B
NEW QUESTION # 77
SCOTT is a user in the database.
Evaluate the commands issued by the DBA:
Which statement is true regarding the execution of the above commands?
- A. Statement 1 would not execute because the IDENTIFIED BY <password> clause is missing.
- B. Statement 1 would not execute because the WITH GRANT option is missing.
- C. Statement 2 would not execute because system privileges and object privileges cannot be granted together in a single GRANT command.
- D. Statement 3 would not execute because role and system privileges cannot be granted together in a single GRANT statement.
Answer: C
NEW QUESTION # 78
Examine the data in the ENPLOYEES table:
Which statement will compute the total annual compensation tor each employee
- A. SELCECT last_namo, (monthly_salary * 12) + (monthly_commission_pct * 12) AS annual_comp FROM employees
- B. SECECT last_namo, (menthy_salary + monthly_commission_pct) * 12 AS annual_comp FROM employees;
- C. SELCECT last_namo, (monthly_salary * 12) + (menthy_salary * 12 * monthly_commission_pct) AS annual_comp FROM employees
- D. SELCECT last_namo, (monthly_salary * 12) + (menthy_salary * 12 * NVL (monthly_commission_pct, 0)) AS annual_comp FROM employees
Answer: D
Explanation:
The correct statement for computing the total annual compensation for each employee is option C. This is because the monthly commission is a percentage of the monthly salary (indicated by the column name MONTHLY_COMMISSION_PCT). To calculate the annual compensation, we need to calculate the annual salary (which is monthly_salary * 12) and add the total annual commission to it.
Here's the breakdown of the correct statement, option C:
* (monthly_salary * 12) computes the total salary for the year.
* NVL(monthly_commission_pct, 0) replaces NULL values in the monthly_commission_pct column with 0, ensuring that the commission is only added if it exists.
* (monthly_salary * 12 * NVL(monthly_commission_pct, 0)) computes the annual commission by first determining the monthly commission (which is a percentage of the monthly salary), and then multiplying it by 12 to get the annual commission.
* Finally, (monthly_salary * 12) + (monthly_salary * 12 * NVL(monthly_commission_pct, 0)) adds the annual salary and the annual commission to get the total annual compensation.
The other options are incorrect:
* Option A is incorrect because it adds the monthly_commission_pct directly to the monthly_salary, which does not consider that monthly_commission_pct is a percentage.
* Option B is incorrect because it adds the commission percentage directly without first applying it to the monthly salary.
* Option D is incorrect because it does not handle the NULL values in the commission column, which would result in a NULL total annual compensation whenever the monthly_comission_pct is NULL.
References:
* Oracle Documentation on NVL function: NVL
* Oracle Documentation on Numeric Literals: Numeric Literals
NEW QUESTION # 79
Examine the structure of the MEMBERS table: (Choose the best answer.)
Examine the SQL statement:
SQL > SELECT city, last_name LNAME FROM MEMBERS ORDER BY 1, LNAME DESC; What would be the result execution?
- A. It displays all cities in descending order, within which the last names are further sorted in descending order.
- B. It fails because a column number and a column alias cannot be used together in the ORDER BY clause.
- C. It fails because a column alias cannot be used in the ORDER BY clause.
- D. It displays all cities in ascending order, within which the last names are further sorted in descending order.
Answer: D
NEW QUESTION # 80
Examine the data in the EMPLOYEES table:
Which statement will compute the total annual compensation for each employee?
- A. SELECT last _ name, (monthly _ salary * 12) + (monthly_ commission _ pct * 12) AS FROM employees:
- B. SELECT last _ NAME (monthly_ salary + monthly _commission _ pct) * 12 AS annual_ comp FROM employees;
- C. SELECT last _ name, (monthly_ salary * 12) + (monthly_ salary * 12 * NVL (monthly_ commission _pct, 0)) AS annual _comp
- D. select last _ name, (monthly_ salary * 12) + (monthly_ salary * 12 *monthly_ commission_ pct) AS annual_ camp FROM employees
Answer: C
NEW QUESTION # 81
Which statement is true about SQL query processing in an Oracle database instance? (Choose the best answer.)
- A. During optimization, execution plans are formulated based on the statistics gathered by the database instance, and the lowest cost plan is selected for execution.
- B. During row source generation, rows that satisfy the query are retrieved from the database and stored in memory.
- C. During execution, the Oracle server may read data from storage if the required data is not already in memory.
- D. During parsing, a SQL statement containing literals in the WHERE clause that has been executed by any session and which is cached in memory, is always reused for the current execution.
Answer: C
NEW QUESTION # 82
Which two statements are true?
- A. Neither CASE nor DECODE is a function.
- B. CASE is a function and DECODE is not.
- C. AIl conditions evaluated using DECODE can also be evaluated using CASE.
- D. Both CASE and DECODE are functions.
- E. All conditions evaluated using CASE can also be evaluated using DECODE.
- F. DECODE is a function and CASE is not.
Answer: C,F
NEW QUESTION # 83
Examine the data in the CUST_NAME column of the CUSTOMERS table:
You want to display the CUST_NAME values where the last name starts with Mc or MC.
Which two WHERE clauses give the required result?
- A. WHERE UPPER (SUBSTR (cust_name, INSTR(cust_name, '')+1)) LIKE UPPER ('MC%')
- B. WHERE SUBSTR (cust_name, INSTR (cust_name, '') +1) LIKE 'Mc%' OR 'MC%'
- C. WHERE INITCAP (SUBSTR (cust_name, INSTR(cust_name, '')+1)) LIKE 'Mc%'
- D. WHERE SUBSTR (cust_name, INSTR (cust_name, '') +1) LIKE 'Mc%'
- E. WHERE INITCAP (SUBSTR (cust_name, INSTR(cust_name, '')+1)) IN ('MC%', 'Mc%)
Answer: D
NEW QUESTION # 84
On your Oracle 12c database, you invoked SQL *Loader to load data into the EMPLOYEEStable in the HR schema by issuing the following command:
$> sqlldr hr/hr@pdb table=employees
Which two statements are true regarding the command? (Choose two.)
- A. It succeeds with default settings if the EMPLOYEEStable belonging to HR is already defined in the database.
- B. It fails if the HR user does not have the CREATE ANY DIRECTORYprivilege.
- C. It fails because no SQL *Loader data file location is specified.
- D. It fails because no SQL *Loader control file location is specified.
Answer: A,B
Explanation:
Explanation/Reference:
NEW QUESTION # 85
View the exhibits and examine the structures of the COSTS and PROMOTIONS tables.
Evaluate the following SQL statement:
SQL> SELECT prod_id FROM costs
WHERE promo_id IN (SELECT promo_id FROM promotions
WHERE promo_cost < ALL
(SELECT MAX(promo_cost) FROM promotions
GROUP BY (promo_end_date-
promo_begin_date)));
What would be the outcome of the above SQL statement?
- A. It displays prod IDs in the promo with the lowest cost.
- B. It displays prod IDs in the promos with the lowest cost in the same time interval.
- C. It displays prod IDs in the promos which cost less than the highest cost in the same time interval.
- D. It displays prod IDs in the promos with the highest cost in the same time interval.
Answer: C
NEW QUESTION # 86
View the Exhibit and examine the description for the SALES and CHANNELS tables.
You issued this SQL statement:
Which statement is true regarding the result? (Choose the best answer.)
- A. The statement will fail because the subquery in the VALUES clause is not enclosed within single quotation marks.
- B. The statement will execute and a new row will be inserted in the SALES table.
- C. The statement will fail because a subquery cannot be used in a VALUES clause.
- D. The statement will fail because the VALUES clause is not required with the subquery.
Answer: B
NEW QUESTION # 87
The SQL statements executed in a user session are as follows:
Which two statements describe the consequences of issuing the ROLLBACK TO SAVE POINT a command in the session? (Choose two.)
- A. Only the second DELETE statement is rolled back.
- B. The rollback generates an error.
- C. Only the DELETE statements are rolled back.
- D. No SQL statements are rolled back.
- E. Both the DELETE statements and the UPDATE statement are rolled back.
Answer: B,D
NEW QUESTION # 88
Examine these statements which execute successfully:
Both statements display departments ordered by their average salaries.
Which two are true?
- A. Only the first statement will execute successfully if you add E.AVG_SAK to the select list.
- B. Only the first statement will display departments with no employees.
- C. Only the second statement will display departments with no employees.
- D. Both statements will display departments with no employees.
- E. Both statements will execute successfully If you add e.avg_sal to the select list.
- F. Only the second statement will execute successfully if you add E.AVG_SAL to the select list.
Answer: A,D
NEW QUESTION # 89
View the Exhibit and examine the structure of the ORDERS table.
You must select ORDER_ID and ORDER_DATE for all orders that were placed after the last order placed by CUSTOMER_ID 101.
Which query would give you the desired result?
- A. SELECT order_id, order_date FROM ordersWHERE order_date > ALL(SELECT order_date FROM orders WHERE customer_id = 101);
- B. SELECT order_id, order_date FROM ordersWHERE order_date > IN(SELECT order_date FROM orders WHERE customer_id = 101);
- C. SELECT order_id, order_date FROM ordersWHERE order_date > ALL(SELECT MAX(order_date) FROM orders ) AND customer_id = 101;
- D. SELECT order_id, order_date FROM ordersWHERE order_date >ANY(SELECT order_date FROM orders WHERE customer_id = 101);
Answer: A
NEW QUESTION # 90
Which two statements will return the names of the three employees with the lowest salaries?
- A. SELECT last_ name, salary
FROM employees
WHERE ROWNUM <=3
ORDER BY salary - B. SELECT last_ name, salary
FROM employees
FETCH FIRST 3 ROWS ONLY
ORDER BY salary; - C. SELECT last_ name, salary
FROM
(SELECT" FROM employees ORDER BY salary)
WHERE ROWNUM <=3 - D. SELECT last name, salary
FROM employees
ORDER BY salary
FETCE FIRST 3 RONS ONLY; - E. SELECT last_ name, salary
FBOM employees
WEERE
ORDER BY SELECT
ROINUM <= 3
salary FROM
employees);
Answer: C,D
NEW QUESTION # 91
View the Exhibit and examine the structure of the CUSTOMERStable.
Using the CUSTOMERStable, you must generate a report that displays a credit limit increase of 15% for all customers.
Customers with no credit limit should have "Not Available" displayed.
Which SQL statement would produce the required result?
SELECT NVL(TO_CHAR(cust_credit_limit*.15),'Not Available') "NEW CREDIT"
- A. FROM customers;
SELECT NVL(cust_credit_limit*.15,'Not Available') "NEW CREDIT" - B. FROM customers;
SELECT TO_CHAR(NVL(cust_credit_limit*.15,'Not Available')) "NEW CREDIT" - C. FROM customers;
SELECT NVL(cust_credit_limit,'Not Available')*.15 "NEW CREDIT" - D. FROM customers;
Answer: B
NEW QUESTION # 92
......
1z1-071 Sample with Accurate & Updated Questions: https://www.passleader.top/Oracle/1z1-071-exam-braindumps.html
1z1-071 Exam Info and Free Practice Test | PassLeader: https://drive.google.com/open?id=1qI8OnXGfD0uVtt4hFRo5QAk9ZgcW33oX